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6w^2+19w-15=-4w
We move all terms to the left:
6w^2+19w-15-(-4w)=0
We get rid of parentheses
6w^2+19w+4w-15=0
We add all the numbers together, and all the variables
6w^2+23w-15=0
a = 6; b = 23; c = -15;
Δ = b2-4ac
Δ = 232-4·6·(-15)
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{889}}{2*6}=\frac{-23-\sqrt{889}}{12} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{889}}{2*6}=\frac{-23+\sqrt{889}}{12} $
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